Question

If x2 + px + 25 = 0 has equal roots, then p=​

Answer 1

$\large { \underline{ \bf \red{Question:- }}}$

• If x2 + px + 25 = 0 has equal roots, then p=?

$\large { \underline{ \bf \purple{Solution:- }}}$

$⇒ The \: given \: equation i \: s \: x 2+px+25=0 \\ </p><p>⇒ Com-pairing \: it \: with \: ax 2+bx+c=0 \\ </p><p>⇒ We \: get, a=1,b=p and c=25 \\ </p><p>⇒ We \: know, D=b 2−4ac \\ </p><p></p><p>D=(p) 2−4(1)(25)$

$=p2−100</p><p></p><p> \\ For \: equal \: roots D=0</p><p></p><p> \\ ∴  p2−100=0</p><p></p><p> \\ ∴  p2=100</p><p></p><p> \\ ∴  p=10</p><p></p><p>$

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