Question

if x2+px+q and x2+lx+m are both divisible by x+a, show that a=m-q/l-p

Answer 1

Since they are divisible by x+a, put (-a) in the expressions and equate to zero.

Hence,

a²-ap+q=0

a²-al+m=0

Subtracting,

a(p-l)=q-m

a=(m-q)/l-p

Answer 2

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