If x2+ px +q=(x+ a) (x +b)then factorise x2 pxy + qy2
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( x + a )( x + b ) = x² + (a+b) x + ab
∵ x² + px + q = ( x + a )( x + b )
∴ x² + px + q ≡ x² + (a+b)x + ab
∴ p = a+b, q = ab
∴ x² + pxy + qy² = x² + (a+b)xy + aby²
. . . . . . . . . . . . . = x² + axy + bxy + aby²
. . . . . . . . . . . . . = x( x + ay ) + by( x + ay )
. . . . . . . . . . . . . = ( x + ay )( x + by ) ..................... Ans.
∵ x² + px + q = ( x + a )( x + b )
∴ x² + px + q ≡ x² + (a+b)x + ab
∴ p = a+b, q = ab
∴ x² + pxy + qy² = x² + (a+b)xy + aby²
. . . . . . . . . . . . . = x² + axy + bxy + aby²
. . . . . . . . . . . . . = x( x + ay ) + by( x + ay )
. . . . . . . . . . . . . = ( x + ay )( x + by ) ..................... Ans.
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answer of the given question is (x-by) (x-ay)
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