Question

if x²+x+1=0 then what is the value of x​

Answer 1

Answer:

(-1+sqrt(3)i)/2 and (-1-sqrt(3)i)/2

Step-by-step explanation:

Answer 2

Here we are given an equation  x²+x+1=0

We have to solve for x

In order to find the value of 'x' we will have to use the following formula

$x=\frac{-b\left \ {{+} \atop {-}} \right. \sqrt{b^{2}-4ac } }{2a}$

Now here

a = 1

b=1

c=1

Putting the values of a, b and c in the above formula

$x=\frac{-1\left \ {{+} \atop {-}} \right.\sqrt{1^{2} -4\times1\times1} }{2\times1}$

  $=\frac{-1\left \ {{+} \atop {-}} \right.\sqrt{1-4} }{2} \\=\frac{-1\left \ {{+} \atop {-}} \right.\sqrt{-3} }{2} \\\\=\frac{-1\left \ {{+} \atop {-}} \right.\sqrt{3}\times\sqrt{-1} }{2}\\=\frac{-1\left \ {{+} \atop {-}} \right.\sqrt{3}i }{2}$

So, value of x will be $\frac{-1\left \ {{+} \atop {-}} \right.\sqrt{3}i }{2}$