If x2 + x + 1 is a factor of x4 + ax2 + b, then find the values of a and b.
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Answer:
x^2 - 3x + 2 = (x - 2)(x - 1)
x = 1, x = 2 make f(x) zero :
x = 1,
1^4 - a(1)^3 + b = 0
a - b = 1
x = 2,
2^4 - a(2)^3 + b = 0
16 - 8a + b = 0
-8a + b = -16
=>
a - b = 1
-8a + b = -16
a = 15/7, b = 8/7
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Step-by-step explanation:
Answered by
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as now taking x as coefficient so what we get is that.
1-a = 0 thus, a=1
b-a =0 thus, b=a
so the answer is that
a =1 as well as b =1.
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