Question

if x2-x-2=0 ,then the value of x is​

Answer 1

x^2-x-2=0

Here,

a=1

b=-1

c=-2

So,

b^2-4ac

=(-1)^2-4. 1. (-2)

=1+8

=9

By quadratic formula,

$x = \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac} } {2a} \\ x = \frac{ - ( - 1) \binom{ + }{ - } \sqrt{ { (- 1)}^{2} - 4 \times 1 \times ( - 1 ) } }{2 \times 1 } \\ x = \frac{1 \binom{ + }{ - } \sqrt{1 + 4} }{2} \\ x = \frac{1 \binom{ + }{ - } \sqrt{5} }{2} \\ so \\ x = \frac{1 + \sqrt{5} }{2} \\ or \\ x = \frac{1 - \sqrt{5} }{2}$

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Answer 2

Answer:

x=-1,2

Step-by-step explanation:

x^2-x-2=0

x^2-2x+x-2=0

x(x-2)+1(x-2)=0

(x+1)(x-2)=0

x+1=0. ,x-2=0

x=-1. ,. x=2

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