Question

if x²-x-6 and x²+3x-18 have a common factor (x-a) then find the value of a.​

Answer 1

Answer:

3

Step-by-step explanation:

given x-a is a factor

so, x-a=0

x=a substitute in both the equations .

1st equation becomes a^2-a-6 =0 that means

a^2 = a +6

and 2nd equation becomes a^2+3a -18=0

that implies

a +6 +3a -18 =0

4a-12=0

4a=12

a= 3