if x²-x-6 and x²+3x-18 have a common factor (x-a) then find the value of a.
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1
Answer:
3
Step-by-step explanation:
given x-a is a factor
so, x-a=0
x=a substitute in both the equations .
1st equation becomes a^2-a-6 =0 that means
a^2 = a +6
and 2nd equation becomes a^2+3a -18=0
that implies
a +6 +3a -18 =0
4a-12=0
4a=12
a= 3
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