Question

if x2-x-6 andx2+3x-18 have a common factor X-a then find the value of a​

Answer 1

Answer:

• x2-x-6=0
• x2-3x+2x-6=0
• x(x-3)+2(x-3)=0
• (x-3)(x+2)=0
• x2+3x-18=0
• x2+6x-3x-18=0
• x(x+6)-3(x+6)=0
• (x+6)(x-3)=0
• therfore x-3 is common in both equations therefore a=3