if x2-x-6 andx2+3x-18 have a common factor X-a then find the value of a
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- x2-x-6=0
- x2-3x+2x-6=0
- x(x-3)+2(x-3)=0
- (x-3)(x+2)=0
- x2+3x-18=0
- x2+6x-3x-18=0
- x(x+6)-3(x+6)=0
- (x+6)(x-3)=0
- therfore x-3 is common in both equations therefore a=3
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