Question

If x² + xy + y² = 2x+3y=7, then what is the
value of x+y?

Answer 1

Answer:

x^2 + xy = 2y^2

x^2 -2xy + y^2 = 3y^2 -3xy

(x-y)^2 = -3y(x-y)

x-y=0 or x-y=-3y, which can be any value.

Choose any number, a. Then

-3y=a, so y = -a/3, x = 2a/3 will give x-y=a and will also solve the equation.

Conclusion: there is no one value for x-y you can deduce from this equation.

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Answer 2

x^2+x.y-2y^2=0

or. x^2-x.y+2x.y-2y^2=0

or. x(x-y)+2y(x-y)=0

or. (x-y)(x+2y)=0

Either (x-y)=0. or. (x+2y)=0 or. both zero

x+2y=0.

x=-2y

Value of x-y= -2y-y. = -3y