Math, asked by vidyabharti932, 1 month ago

if x²+y square is equal to 29 and X y is equal to 2, find the value of Ist x+y 2nd x-y 3rd x⁴+y⁴​

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Answers

Answered by kashvichaurasia819
0

Answer:

Given that,

x2 + y2 = 29

x2 + y2 + 2xy – 2xy = 29

(x + y)2 – 2 (2) = 29

(x + y)2 = 29 + 4

x + y = �

(ii) x-y

x2 + y2 = 29

x2 + y2 + 2xy – 2xy = 29

(x – y)2 + 2 (2) = 29

(x – y)2 + 4 = 29

(x – y)2 = 25

(x – y) = � 5

(iii) x4+y4

x2 + y2 = 29

Squaring both sides, we get

(x2 + y2)2 = (29)2

x4 + y4 + 2x2y2 = 841

x4 + y4 + 2 (2)2 = 841

x4 + y4 = 841 – 8

x4 + y4 = 833

Step-by-step explanation:

Kashuuu~

Answered by mabhaviahya786kumar5
0

Answer:

chatting karne aana chahogi

Step-by-step explanation:

only friendly

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