IF X² = Y+Z
Y² = X+Z
Z² = Y+X
find 1/1+x + 1/1+y + 1/1+z
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We can write 1/(1+x) + 1/(1+y) + 1/(1+z)
as {(1+x)(1+x)(1+y)(1+y)(1+z)(1+z)}/(1+x)(1+y)(1+z) ....... [As lCM is (1+x)(1+y)(1+z)]
= (1+x)(1+y)(1+z) = (1+z²-y)(1+x²-z)(1+y²-x) .............. [From the provided values]
Hope that helps !!
as {(1+x)(1+x)(1+y)(1+y)(1+z)(1+z)}/(1+x)(1+y)(1+z) ....... [As lCM is (1+x)(1+y)(1+z)]
= (1+x)(1+y)(1+z) = (1+z²-y)(1+x²-z)(1+y²-x) .............. [From the provided values]
Hope that helps !!
Avishek:
let me see
if i can
can u find the value of (x+1)(y+1)(z+1)?
no
now?
can this be simplified
i dont think so
i dont have this in my option
oh what are the options?
-1 ,2 ,1 ,0
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