Question

If x2 + y2 = 1, then (4x² – 3x)2 + (3y - 4y3)2
2) 2
111
3) 3​

Answer 1

Answer:

Step-by-step explanation:

We putting y ^2 = (-1x^2) that is converting to terms of x

x² * (4x² - 3)² + y² * (3 - 4y²)²

=x² * (4x² - 3)² + (1 - x²) * [3 - (4 - 4x²)]²

= x² * (4x² - 3)² - (x² - 1) * ( 4x² - 1)²

= x² * (4x² - 3)² - x² * ( 4x² - 1)² + ( 4x² - 1)²

= x² [ (4x² - 3)² - ( 4x² - 1)² ]+ ( 4x² - 1)²

= x² [ (4x² - 3 + 4x² - 1)(4x² - 3 - 4x² + 1) ] + ( 4x² - 1)²

= x² * (8x² - 4)(-2) + ( 4x² - 1)²

= -16x^4 + 8x² + 16x^4 - 8x² + 1

= 1

i hope it help u..