Question

If x² + y² =1, then (4x³-3x)² + (3y - 4y³)² =​

Answer 1

Step-by-step explanation:

x

2

+y

2

=1⇒y

2

=1−x

2

P=(3x−4x

3

)

2

+(3y−4y

3

)

2

=x

2

(3−4x

2

)

2

+y

2

(3−4y

2

)

2

=x

2

(3−4x

2

)

2

+(1−x

2

)[3−4(1−x

2

)]

2

=x

2

(3−4x

2

)

2

+(1−x

2

)(4x

2

−1)

2

=x

2

(9+16x

4

−24x

2

)+(1−x

2

)(16x

4

+1−8x

2

)

=9x

2

+16x

6

−24x

4

+16x

4

+1−8x

2

−16x

6

−x

2

+8x

4

∴P=1