Question

If x2 + y2 = 1, then

(a) y y” – (2y’)2 + 1 = 0 (b) y y” + (y’)2 + 1 = 0 (c) y y” – (y’)2

– 1 = 0 (d) y y”

+ (2y’)2 + 1 = 0​

Answer 1

Answer:

Step-by-step explanation:

x^2 + y^2 = 1,

Differentiate w.r.t. x,

2x + 2yy' = 0,

Again differentiate,

2 + 2( yy'' +y'^2) = 0,

or, yy'' + y'^2 + 1 = 0,

ANS is (B).