Question

if x²+y²= 10 and xy=5 find the value of 3(x+y)²-2(x-y)²

Answer 1

given that x^2 + y^2 =10

and xy = 5

the equation

3(x+y)^2 -2 (x-y)^2

becomes

3(x^2+y^2+2xy) - 2(x^2+y^2-2xy)

3(10+2(5))-2(10-2(5))

3(10+10)-2(10-10)

3(20)-2(0)

60-0=60

Answer 2

Answer:

given that x^2 + y^2 =10

and xy = 5

the equation

3(x+y)^2 -2 (x-y)^2

becomes

3(x^2+y^2+2xy) - 2(x^2+y^2-2xy)

3(10+2(5))-2(10-2(5))

3(10+10)-2(10-10)

3(20)-2(0)

60-0=60

Step-by-step explanation: