if x2+y2=107xy then prove that 2log(x-y)=log 3+log 5+log 7+log x+log y
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Step-by-step explanation:
x^2+y^2=107xy
Subtracting 2xy on both sides
(x-y)^2=105xy
Applying log on both sides
2 log(x-y)=log(105xy)=log(3*5*7*X*y)
2log(x-y)=log3+log5+log7+logx+logy
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