Question

If x²+y²=13 & xy=6,find the value of x-y​

Answer 1

Answer:

Step-by-step explanation:

(x-y)^2 = x^2+y^2-2xy

(x-y)^2 = 13 + {2 (6)}

(x-y)^2 = 13 + 12

(x-y)^2 = 25

(x-y) = under root 25

(x-y) = 5