Question

If x² + y² = 13 and xy = 6, find the value of: x-y
please solve step by step​

Answer 1

Answer:

Step-by-step explanation:

(x-y)2=x2-2xy+y2

=x2+y2-2xy

=13-2*6

=13-12

=1

(x-y) =1

Answer 2

Answer:

x - y = ± 1

Step-by-step explanation:

GIVEN:

x^2 + y^2 = 13

xy = 6

to find: x - y

using the algebraic identity,

[ (a - b)^2 = a^2 + b^2 - 2ab]

(x - y)^2 = x^2 + y^2 - 2xy

(x - y)^2 = 13 - 2(6)

(x - y)^2 = 13 - 12

(x - y)^2 = 1

x - y = ± 1