Question

if X2+Y2=18xy then prove that 2log(x-y)=4log2+logx+log y
step by step please ​

Answer 1

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Step-by-step explanation:

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Answer 2

Question :- if x² + y² = 18xy then prove that 2log(x - y) = 4log2 + log x+log y ?

Solution :-

→ x² + y² = 18xy

Subtracting 2xy from both sides,

→ x² + y² - 2xy = 18xy - 2xy

→ (x² + y² - 2xy) = 16xy

comparing LHS part with a² + b² - 2ab = (a - b)²,

→ (x - y)² = 2⁴xy

Taking log both sides now, we get,

→ log{(x - y)²} = log(2⁴xy)

in LHS now, using :-

• log(a^b) = b * log(a)

in RHS , using :-

• log(a * b * c) = log(a) + log(b) + log(c)
• log(a^b) = b * log(a)

we get :-

→ 2 * log(x - y) = log(2⁴) + log(x) + log(y)

Or,

→ 2log(x - y) = 4log2 + log x+log y . (Proved).