Question

if x2 +y2=27×y,then above that log x-y/5=1/2 (logx+logy)
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Answer 1

sorry don't know find from the google

Answer 2

Step-by-step explanation:

$(x² + y² - 2xy) = 25xy$

$(x - y)² = 25xy$

$(x - y) = 5\sqrt{xy}$

$\frac{(x - y)}{5} =\sqrt{xy}$

$Taking \: log \: both \: side$

$log\frac{(x-y)}{5} = log\sqrt{xy}$

$log\frac{(x-y)}{5} = log(xy)^½$

$log\frac{(x-y)}{5} =\frac{1}{2}log(xy)$

$log\frac{(x-y)}{5} =\frac{1}{2}(logx+logy)$