Question

If x2 +y2 =27xy then prove that 2log(x - y)=2log5+logx+logy.
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Answer 1

Step-by-step explanation:

To prove ,

2log(x-y) = 2log5 + logx + logy

Consider ,

Subtract 2xy on both sides of the equation.

Apply log on both sides,

Log (x-y)^{2} = log25xy

It can be written as ,

2 log(x-y) = log 5^2 + logx+logy

=> 2 log (x-y) = 2log5 + log x + logy

Hence proved

hope this helps