Question

If `x²+y²=29 & xy=2,then find the value of (i) x+y (ii)x-y

Answer 1

Answer:

$( x + y) ^{2} = { x}^{2} + {y}^{2} + 2xy$

${(x + y)}^{2} = 29 + 2 \times 2$

${(x + y)}^{2} = 29 + 4$

${(x + y)}^{2} = 33$

$x + y = \sqrt{33}$