Question

If x2

+ y2

= 29 and xy = 2, find the value of

(i) x+y (ii) x-y (iii) x4

+y4​

Answer 1

Step-by-step explanation:

(x+y)²=x²+y²+2xy

=(x²+y²)+2*3

=29+4

(x+y)²=33

x+y=√33

(x-y)²=x²+y²-2xy

=(x²+y)³-2*2

=29-4

(x-y)²=25

x-y =5

Answer 2

Answer$\sqrt{33}$

Step-by-step explanation:

$(x^{2} +y^{2})^{2} =x^{2} +y^{2} +2xy$

$(x^{2} +y^{2})^{2} =29 + 2*2$

$(x^{2} +y^{2})^{2} =33$