Question

If x2+y2=29xy then find the value of 2log (x-y)

Answer 1

Given x2+y2=29xy
subtract 2xy on both sides
X2+y2-2xy=29xy-2xy ((a-b) 2=a2+b2-2ab)
(x-y) 2=27xy
Add log on both sides
log(x-y) 2=log27xy
2log(x-y) =log 3(3).x.y (logx(a) =a logx)
2log(x-y)=3log3+logx+log (logx(a) =a logx)

Therefore value of 2log(x-y) =3log3+logx+logy,,