Question

If X2+Y2=29XY,then prove that 3log3+logx+logy

Answer 1

Answer:

x² + y² = 29xy

Subtract 2xy on both sides

x² + y² - 2xy = 29xy - 2xy

(x - y)² = 27xy  [(a-b)^2 formula]

Taking log on both sides

log(x - y)² = log27xy

log(x - y)² = log27 + logx + logy [ log abc= log a +log b+log c]

log(x - y)² = log3³ + logx + logy

2log(x - y) = 3log3 + logx + logy

Thus,Proved

Answer provided by Gauthmath

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