Question

If x2 + y2 = 2log(x + y), find dy/dx​

Answer 1

Step-by-step explanation:

x^2+y^2=2log(x+y)

differentiating wrt x

2x+2ydy/dx = 2/(x+y) × (1+dy/dx)

x + y dy/dx = (1+dy/dx) / x+y

( x+y) (x+ydy/dx) = 1+dy/dx

x^2 +xy + xydy/dx + y^2 dy/dx = 1+ dy/dx

(xy + y^2-1) dy/dx = 1 - x^2 - xy

dy/dx = (1 - x^2 - xy) / (xy + y^2-1)

mark me as brainliest