Math, asked by deswaldhruv333, 10 months ago

if x2+y2= 34 and xy=1 then find the value of x+y

Answers

Answered by pendyalamanu777
2

Answer:

x+y = 6

Step-by-step explanation:

FORMULA

(a+b)² = a² + b²+ 2×a×b

  • x² + y² = 34
  • xy = 1

(x+y)² = (x² + y²) + 2 (xy)

(x+y)² = 34 + 2 × 1

= 34 + 2

(x+y)² = 36

x+y = 36

x+y = 6

Answered by VANSHTOLANI1214
0

Answer:

6

Step-by-step explanation:

x^2 +y^2=34

We know,

(a+b)^2 =a^2+b^2=2ab

x^2 +y^2=34+2xy

x^2+y^2=34+2*1[xy=1](given)

x^2+y^2=36

(x+y)^2=36

(x+y)=√36

x+y=6

#Einstein hain hum

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