Question

if x2+y2=3xy then find the value of 2log(x-y)​

Answer 1

Answer:

23xy

Step-by-step explanation:

Log (x+y/ 5) = 1/2 (logx + logy)

log (x+y/ 5) = 1/2 (log xy)

log (x+y/ 5) = log (xy)^(1/2)

(x+y/ 5) = (xy)^(1/2)

(x+y/ 5)^2 = xy

(x² + y² + 2xy) / 25 = xy

x^2 + y^2 = 23xy.

Answer 2

Answer is log x + log y.

2 log (x-y )

= log (x - y)^2

= log x^2+y^2-2xy

= log xy

Log x+log y