Question

If x2 + y2 = 4 and x-y=3 then find the value of x3-y3​

Answer 1

Hope it helps!

Answer is in the pic

Answer 2

The value is $x^3-y^3=4.5$

Step-by-step explanation:

Given : $x^2+y^2=4$ and $x-y=3$

To find : The value of $x^3-y^3$ ?

Solution :

We have given,

$x-y=3$

Squaring both side,

$(x-y)^2=(3)^2$

$x^2+y^2-2xy=9$

Substitute the value given,

$4-2xy=9$

$-2xy=5$

$xy=-\frac{5}{2}$

Now using the formula,

$x^3-y^3=(x-y)(x^2+y^2+xy)$

Put the values,

$x^3-y^3=(3)(4+(-\frac{5}{2}))$

$x^3-y^3=(3)(4-2.5)$

$x^3-y^3=(3)(1.5)$

$x^3-y^3=4.5$

Therefore, the value is $x^3-y^3=4.5$

#Learn more

If x2+y2 =49and x-y=3 then find the value of x3-y3

https://brainly.in/question/4800087