Question

if x²+y²=4q and x-y =3 then find the value of x³-y³



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Answer 1

Answer: (12q-27)/2

Explanation:

Given that,

x-y=3, x²+y²=4q.

(x-y)² = x²+y²+2xy

3² =4q-2xy

9 = 4q-2xy

Find xy.

xy = (4q-9)/2

Use this formula : x³-y³=(x-y)(x²+y²+xy)

x³-y³ = (3)(4q-2xy)

Substitute xy in above equation:

x³-y³ = (3)[4q-(4q-9)/2]

x³-y³ = (3) [(8q-4q-9)]/2

x³-y³= (3) [4q-9]/2

x³-y³ = (12q-27)/2

Answer 2

Answer:

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