Question

if x2+y2-4x-6y+13=0 then y:x

Answer 1

Answer:

x2+y2-4x-6y=-13

#BAL

Answer 2

The ratio of the value of y : x = 3 : 2.

Step-by-step explanation:

We have,

$x^2+y^2-4x-6y+13=0$

To find, the ratio of the value of y : x = ?

∴$x^2+y^2-4x-6y+13=0$

=$x^2+y^2-2(x)(2)-2(y)(3)+4+9=0$

$=(x^2-2(x)(2)+4)+(y^2-2(y)(3)+9)=0$

$=(x^2-2(x)(2)+2^{2})+(y^2-2(y)(3)+3^{2})=0$

$=(x-2)^{2}+(y-3)^{2} =0$

∴ $(x-2)^{2}=0$⇒ x - 2 = 0 ⇒ x = 2 or

$(y-3)^{2} =0$ ⇒ y - 3 = 0 ⇒ y = 3

The ratio of the value of y : x = 3 : 2.

Hence, the ratio of the value of y : x = 3 : 2.