Math, asked by arindam1072, 9 months ago

If x2 + y2 = 57, xy = 16 and x is bigger than y, then (x - y) is equal to​

Answers

Answered by madhukarshetty737
12

Answer:

5

Step-by-step explanation:

Given that : x²+y² = 57 and xy = 16

As we know that :

{(x  - y)}^{2}  =  {x}^{2}  +  {y}^{2}  -  2xy

{(x  - y)}^{2}   = 57  -  2 x 16

{(x  -  y)}^{2}  = 57 - 32

{(x - y)}^{2}  = 25

(x - y) = 5

I hope it will be helpful for you...!!

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Answered by shandilyarishit872
3

Answer is 5

Step-by-step explanation:

(x-y)^2 = (x)^2 + (y)^2 - 2xy

= 57-2×16

= 57-32

(x-y)^2 = 25

(x-y) = (x-y)= \sqrt{25}

(x-y) = 5

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