If x² + y² = 5xy Prove that log(x-y)/3 = 1/2(log x + log y)
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something is wrong there i guess
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Hey
here is your answer!!
= x²+y²+2xy = 25xy
= ( x + y )² = 25xy
= x+y = 5 (xy)½
So, log both sides
log (x+y) = log {5 ( xy)½}
= log (x+y) = log 5 + log (xy)½
= log (x+y) - log 5 = 1/2 log xy
= log (x+y/5) = 1/2 log xy [Proved]
Step-by-step explanation:
Hope it helps !!
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