Math, asked by hassan2038, 3 months ago

If x²-y² = 6 and
= 6 and x-y= 2 find the value
of (x+y)²

Answers

Answered by vashimahmed869
1

7⅚ x 0

it is so simple

please do it carefully

Answer:

0.

Answered by harshitha202034
0

Answer:

 {x}^{2}  -  {y}^{2}  = (x + y)(x - y) \\ 6 = (x + y) \times 2 \\  \frac{6}{2}  = x + y \\ \boxed{ \large \underline{ \underline{ 3}} = x + y} \\  \\ x + y = 3 \\ x - y = 2 \\  -  -  -  -  -  \\ 2x = 5 \\  \boxed{ \large x =  \underline{ \underline{ \frac{5}{2} }}} \\  \\ x + y = 3 \\  \frac{5}{2}  + y = 3 \\  y = 3 -  \frac{5}{2}  \\ y =  \frac{6 - 5}{2}  \\  \boxed{ \large y =  \underline{ \underline{ \frac{1}{2}} }} \\  \\  {(x + y)}^{2}  \\  =  {x}^{2}  +  {y}^{2}  + 2xy \\  =  {( \frac{5}{2}) }^{2}  + {( \frac{1}{2}) }^{2} + ( \cancel 2 \times  \frac{5}{ \cancel 2}  \times  \frac{1}{2} ) \\  =  \frac{25}{4}  +  \frac{1}{4}  +  \frac{5}{2}  \\  =  \frac{25 + 1 + 10}{4}  \\  =  \frac{36}{4}  \\  \boxed{ \large {(x + y)}^{2}  = \underline{ \underline{ 9}}}

Similar questions