Question

If x2 + y2 = 60 and x-y=6, then find the value of x3-y3

Answer 1

x^2-y^2=60----(1)
x-y=6----(2)
x^2-y^2=60
(x+y)(x-y)=60
(x+y)*6=60
(x+y)=60/6
x+y=10---(3)
add(3) and (2)
2x=16
x=16/2
x=8
Substitute x=8 in (3) you get
y=2
therefore
x^3-y^3=8^3-2^3

=512-8=504

Answer 2

Answer:

x^2-y^2=60----(1)

x-y=6----(2)

x^2-y^2=60

(x+y)(x-y)=60

(x+y)*6=60

(x+y)=60/6

x+y=10---(3)

add(3) and (2)

2x=16

x=16/2

x=8

Substitute x=8 in (3) you get

y=2

therefore

x^3-y^3=8^3-2^3

=512-8=504

Step-by-step explanation: