If x2 + y2 = 6xy, prove that 2 log (x + y) = logr + logy + 3 log 2
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Answer:
4log +132 +xy log 5,2log x, Y 469 +log 28 xy
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Step-by-step explanation:
x2+y2=6xy
x2+y2=3×2xy
apply log on this equation
x2 log + y2 log = 3×2 log xy
2log(x+y)= log x + logy + 3×2log
2log (x+y) = log x + log y + 3log 2
hence proved..
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