Question

If x² + y² = 6xy, prove that 2 log (x + y) = logx + logy + 3 log 2

Answer 1

x^2+y^2=6xy
Adding 2xy on both sides
x^2+y^2+2xy=8xy
(x+y)^2= 8xy
Putting log on both sides
log(x+y)^2=log 8xy
2log(x+y)=logx+logy+log 8
2log(x+y)=logx+logy+log2^3
2log(x+y)=logx+logy+3log 2

Answer 2

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