if x2+y2+6xy, prove that 2log(x+y)=logx+logy+3log2
chrisle:
I believe it is x^2+y^2=6xy
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=> log(x+y)²==log(2³xy)
=> x²+2xy+y²==8xy //given x²+y²=6xy...put this in LHS
=>6xy+2xy=8xy≡8xy
∴ RHS=LHS Proved!
=> x²+2xy+y²==8xy //given x²+y²=6xy...put this in LHS
=>6xy+2xy=8xy≡8xy
∴ RHS=LHS Proved!
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