Question

If X2+Y2=6xy, prove thay 2log(x+y)=logx+logy+3log2​

Answer 1

Answer:

Answer:

x2+y2=6xy

⇒(x+y)2−2xy=6xy

⇒(x+y)2=8xy

Taking log both sides,

log(x+y)2=log(8xy)

⇒2log(x+y)=log8+logx+logy

⇒2log(x+y)=log23+logx+logy

⇒2log(x+y)=3log2+logx+logy