Question

If x²+y² = 79xy show that

2log(x+y) =4log3+logx+logy.

Answer 1

Your answer is given :

.: x²+y² = 79xy

show 2log(x+y)=4log3+logx +logy

Log(x+y)^2=log(x•y•81)

x²+y²+2xy=81xy

79xy+2xy=81xy. ( x²+y²=79xy)

81xy=81xy.(.:loga^m+loga^n=log a^mn)

Plz mark brainliest.

Answer 2

hope it may help you dear :-)
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