If x2+y2=7xy then show that 2log (x+y)=logx+logy+2log3
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Answer:
7xy can be written as 9xy-2xy
:.x2+y2=9xy-2xy
x2+y2+2xy=9xy
(x+y)2=9xy
Applying log on both sides
log(x+y)2=log9xy
since,logxpowerm=mlogx
log(x+y)2=2log(x+y)
since , logabc= loga+logb+logc
log9xy=log9 +logx+log y
=2log3+logx+logy
:.2log(x+y)=logx+log y+2log3
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