Question

if x2 + y2 = 80 and xy = 12, find the value of (x - y)​

Answer 1

Answer:

Given :

➡️ x^2 + y^2 = 80

➡️ xy = 12

To find :

➡️ (x-y)

Solution :

we know that

(x-y)^2 = x^2 + y^2 - 2xy

substituting the values of x^2 + y^2 and xy here, we get

(x-y)^2 = 80-2(12)

that is, (x-y)^2 = 80-24 = 56

that is, (x-y) = √56 = 2√14

Hence,the value of (x-y) is 2√14.