Question

If x²+y²=86 and xy= -16, find the value of (x-y)²

Answer 1

Step-by-step explanation:

Given : x+y=2 , x²+y²=2

X=2-y(put this in eqn 2)

(2–y)²+y²=2

4+y²-4y+y²=2

2y²-4y+2

2(y²-2y+1)

Y²-1y-1y+1

Y(y-1)-1(y-1)

Y-1=0

Y=1

AND HENCE X=2–Y

X=2–1

X=1

SO,XY=1*1=1

HOPE IT HELP ☺️