Question

if X2+ y2= 90 and xy= 27, then find the value of x3- y3 when x3-y3 when x>y​

Answer 1

Answer:

702

Step-by-step explanation:

We know x^2+y^2-2xy=(x-y)^2

So, (x-y)^2=90-54=36

x-y=+6(x>y)

Now x^3-y^3=(x-y)(x^2+y^2+xy)

=6*(90+27)

=702

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Answer 2

Answer:

702

Step-by-step explanation:

Answer is 702

Hope it is helpful!!!