if x²+y²/x²-y²=17/8,then find the value of ,(i)x:y (ii)x³+y³/x³-y³
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Answer:
(i) x2 + y2/x2 – y2 = 17/8
Applying componendo and dividendo rule,
x2 + y2 + x2 – y2/x2 + y2 – x2 + y2 = 17 + 8/17 – 8
2x2/2y2 = 25/9
x2/y2 = 25/9
x/y = 5/3
x : y = 5 : 3
(ii) Taking cube on both sides,
x3/y3 = 125/27
Applying componendo and dividendo rule,
x3 + y3/x3 – y3 = 125 + 27/125 – 27
x3 + y3/x3 – y3 = 152/98
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Answer: (i) x2 + y2/x2 – y2 = 17/8. Applying componendo and dividendo rule,. x2 + y2 + x2 – y2/x2 + y2 – x2 + y2 = 17 + 8/17 – 8.
Step-by-step explanation:
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