Math, asked by rashmiankit786, 6 months ago

if x²+y²÷x²-y²=17÷8 then find the value of xy​

Answers

Answered by bhowmik2018piu
0

Step-by-step explanation:

x²+y²÷x²-y²=17÷8

x²+y²/ x²-y²= 17/8

8x²+8y²= 17x²- 17y²

17x² -8x²= 17y²+8y²

9x²=25y²

x²/y²= 25/9

x/y= √25/9

x/y= 5/3

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