If x2 + y2 + z2 = 2(x - y - Z)-3, then the value of 2x - 3y + 4z is
(A) 5
(B) 6
(C) 3
(D) 1
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Taking all left side we get,
(x²-2x+1)+(y²-2y+1)+(z²-2z+1) = 0
(x-1)²+(y-1)²+(z-1)² = 0
x = 1, y = 1 and z = 1
putting we get,
2*1-3*1+4*1 = 3 (Ans)
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