If x2 + y2 + z2 = 28. x+y+z= 6, then xy + yz + xz is equal to
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Answered by
3
Answer:
4
Step-by-step explanation:
6^2-2*(xy+yz+xz)=28
xy+yz+xz=(36-28)/2
=4
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Answered by
17
Answer:
4
Step-by-step explanation:
answer in attachment.
the identity mentioned at top is ( x^2 + y^2 + z^2) = x^2+y^2+z^2+2xy+2yz+2zx
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