Question

if x²+y²+z²=40 and xy+yz+zx=12, ,then find the value of X+y+z ​

Answer 1

Answer:

• (x+y+z)^2 = x^2+ y^2+ z^2+ 2(xy+yz+zx)
• So now, put the known values and get the value of (x+y+z)^2
• So , (x+y+z)^2 = 40 + 2×12

• Hence , (x+y+z) =
• $\sqrt{64 }$
• which is = +8 & -8

Answer 2

Answer:

Find x + y + z, if x2 + y2 + z2 = 40 and xy + yz + zx =

.

Find x + y + z, if x2 + y2 + z2 = 40 and xy + yz + zx =

.