Question

If x2p+1 = xP+5, then find p.​

Answer 1

Step-by-step explanation:

$\: \: \: \: \: {x}^{2} p + 1 = xp + 5 \\ = > \: {x}^{2} p - xp - 5 + 1 = 0 \\ = > {x}^{2} p - xp - 4 = 0 \\ = > {x}^{2} p - 4xp + xp - 4 = 0 \\ = > x(x p- 4) + 1(xp - 4) = 0 \\ = > (xp - 4)(x + 1) = 0$

xp-4=0. |. x+1=0

xp=4. |. x= -1

p=. 4/x |

p=4/-1 |

p=-4 Ans.

Answer 2

Answer:

P=4

Step-by-step explanation:

• x2p+1 = xp+5
• 2p+1 = p+5                [Cancel x on both sides]
• 2p+1-1 = p+5-1           [Subtract 1 on both sides]
• 2p =  p+4
• 2p-p =  p+4-p             [Subtract p on both sides]
• p = 4
• Therefore, p = 4